Homework assignments for Math 313-C1
There's no new homework assignment for this week.
Tenth homework assignment, due 12/01/2000:
- Section 10.5, problems 5, 10, 12, 16
- Additional problem for graduate credit: none
Ninth homework assignment, due 11/17/2000:
- Section 7.8, problem 39
- Section 8.5, problems 7, 8, 9
- Additional problem for graduate credit: none
Eighth homework assignment, due 11/10/2000:
- Section 7.8, problems 7, 12, 22, 23 (a)+(b)
- Additional problem for graduate credit: Section 7.8, 27
No homework due on 11/03/2000.
No homework due on 10/27/2000.
Seventh homework assignment, due 10/20/2000:
- Section 6.6, problems 10, 14, 19, 20
- Additional problem for graduate credit: Section 6.6, problem
18
Sixth homework assignment, due 10/13/2000:
- Section 6.6, problems 2, 3, 8
- Additional problem for graduate credit: Section 6.6, problem
15
Fifth homework assignment, due 10/06/2000:
- Section 5.8, problems 10, 11, 24
- Additional problem for graduate credit: none
Fourth homework assignment, due 09/22/2000:
- Section 3.6, problems 16, 19, 21
- Find out what's wrong with the following argument:
Claim: If M is a finite set of people, then all the people in M
are the same age.
Proof: Let n be the number of people in M. We proceed by
induction on n.
- n=1: There's nothing to show in this case.
- Assume that the claim is true for some n. Consider the set M
with elements x_1,...,x_(n+1). Let A={x_1,...,x_n}, and let
B={x_2,...,x_(n+1)}. By induction, all people in A are the same
age, and all people in B are the same age. Hence, if y is an
element of the intersection of A and B, then x_1 and y are the same
age, and x_(n+1) and y are the same age. Hence, x_1 and x_(n+1) are
the same age, and we are done.
- Additional problem for graduate credit: Prove that
.
Third homework assignment, due 09/15/2000:
- Section 3.6, problems 5 (a) and (b), 6, 10, 13
- Additional problem for graduate credit:
Fact: Let N and p be positive integers. Then there exists some
positive integer M such that for every map f: {1,...,M} -->
{1,...,N}, there exist positive integers n and q such that
f(n)=f(n+q)=...=f(n+(p-1)q).
Use this fact to prove the following claim: Let N, p, and q0 be
positive integers. Then there exists some positive integer M such
that for every map f: {1,...,M} --> {1,...,N} there exist
positive integers n and q>=q0 such that
f(n)=f(n+q)=...=f(n+(p-1)q).
Second homework assignment, due 09/11/2000 (note the new due
date!):
- Section 2.4, problems 5, 11, 12 (assume that n is distinct from
m), 17
- Additional problem for graduate credit: Section 2.4, Problem
13
First homework assignment, due 09/01/2000:
- Section 1.8: Problems 3, 4(a), 8
- Prove that a 2^n by 2^n board with one corner square removed
admits a perfect cover of L-shaped tiles (see figures).
| 2^n by 2^n board with one corner square removed |
 |
| Tile (consists of three small squares) |
 |
- Additional problem for graduate credit: Section 1.8, Problem
4(b)
Peter Brinkmann
$Date: 2002-01-21 00:59:46-06 $
