Hints for Homework Assignment 2

General remarks

Problem 1: This problem is of the same type as those on the first HW assignment, and should be done in the same manner at the outcome space level (with equally likely probabilities); that is, you need to

Problems 2 - 4: These are theoretical problems, to be done within the Kolmogorov axiom framework, as the examples worked in class last week. In addition to the basic rules (Kolmogorov axioms, inclusion-exclusion, average rule, etc.), you are free to use any properties and rules derived in class, but you should say which rule you are using in each step. For most of these problems, you should draw a picture to see what is going on. For set-theoretic identities (such as (A union B)c = Ac intersection Bc), a picture suffices as justification.

If a problem does not specifically say that two events are independent, then they are probably not and you should not assume that they are. (As a general rule, you should never add assumptions to those given in the problem. The problems are formulated such that they can be solved with the given assumptions and data, and no additional information is necessary. By the same token, the problems do not contain redundant data or assumptions. If you get an answer without using all of the given data in a problem, you are probably doing something wrong.)

Problems 5 - 6: These are word problems involving rules involving conditional probabilities such as Bayes' rule, the multiplication rule, or the average rule. (We will do several problems of this type in class on Monday and Wednesday. See also Example 3 in Section 1.5.) As indicated on the problem sheet, you should do these problems rigorously within the framework of conditional probabilities. To that end, you need to

The first two steps above, which set up the problem as a mathematical problem, are usually the most difficult part of solving the problem, and it is essential that you do this properly. This means, for instance, to know when a verbal description refers to a conditional probability (usually hinted at by words are "if", "given", but it could also arise in connection with "proportions" of subpopulations), and when it refers to probabilities of intersections. (Both instances occur within these problems!)

Bayes' rule depends on having a partition of Omega into sets B1, B2, etc. Often, but not always, this partition consists simply of a set and its complement.

Specific comments


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Last modified Mon 03 Feb 2003 06:08:57 PM CST