Some correspondence on the second of the old exam questions:
A student writes: I went through and attempted to complete the second sample worksheet you
gave us on Friday that deals with the adjusted winner procedure (it is #9).
Since there are six items, do bob &carol each receive three since there is
an even amount?
The numbers I got were that Bob would think he received 55% of the total and
that Carol would think she received 60%. Am I correct or way off? I just
want to see if I am doing it wrong before I complete the homework.
My reply: In this problem, there is one place going down the column where
the split is 55-60 for one person, and then the next place gives the split
65-50 the other way. When that happens, you have to do a little algebra and
solve the equation to figure out how to split the item in the middle. I will
talk about this problem in class on Wednesday.
A student writes: I was wondering if before I begin to do the homework problems, if you could
tell me if the solution I came up with for the second in class assignment is
correct. Actually, the reason for this e-mail is that I am pretty sure it is not
correct. I came up with:
B gets 30+13+12(1-x)
C gets 10+20+20+10(x)
So, 43+12-12x=60+10x
55-12x=60+10x
55=60+22x
x= -5/22.
I don't understand why or how I could have come up with a negative fraction
here. I would appreciate an explaination before I do all the homework
probblems and do them all completely wrong, too.
My reply: OK let's rearrange and set things up
Item B C ratio
1 30 20 1.50
5 13 10 1.30
6 12 10 1.20
4 10 10 1.00
3 15 20 .75
2 20 30 .67
If we split so that B gets 156 and C gets 432, then B thinks he's gotten
30+13+12 = 55 and C thinks she's gotten 10+20+30=60, so C gets too much.
If we split so that B gets 1564 and C gets 32, then B thinks he's gotten
30+13+12+10 = 65 and C thinks she's gotten 20+30=50, so C gets too much.
This means it's item 4 that you have to split. I'm not sure where you're
getting the numbers for C.